The Enderman (Boneyard II)

[G.G.]

Hey Folks,
Here's another "why did I wait so long to make one of these" builds. I was so surprised at how much I like the sound of this. It cleans up really nicely with a slight volume knob roll-off or light picking and the dirt has a lovely grain. Highly recommended if you're looking for a sweet Plexi sound. The only problem now is what to do with the other pedals made redundant by this one, because there are several, and they're ones that I like a lot. This is another one with a Minecraft theme, for no particular reason other than I couldn't think of a good name. Eek, just noticed the pube-like thread of hot-melt glue down on the LED. <sigh> there's always something. . . . .

[flanagan0718]

This looks Great! I do have a question for you...Whats with the resistor on the footswitch. Is this for the LED?

[G.G.]

yes, that's the CLR.

a Haberdasher board, BTW.

[flanagan0718]

That's a great idea, is it cool if i try it???

[G.G.]

haha! Of course!! I think it's how some of the DAM pedals are set up, not my invention at all. 

[flanagan0718]

Cool, way better than soldering to the LED lead and covering with electrical tape. Nice profile pic BTW. haha!

[lincolnic]

Wait, the CLR doesn't have to go directly between power and the LED?

mindblown.gif

[pryde]

Awesome Build.

The Boneyard rules. Juice it with an AMZ boost in front and get ready 

[selfdestroyer]

Awesome Build.

The Boneyard rules. Juice it with an AMZ boost in front and get ready 

Agreed, I had a thunderpuss in front of mine for some time. I love how every time I have the Bonyard II on I just can not resist to play a full G chord and feel like Angus Young. lol

Never tried Blue 5mm LEDs for clipping before, whats the Fv compared to Red 5mm?

Awesome looking build by the way, I love the name also.

Cody

[G.G.]

Wait, the CLR doesn't have to go directly between power and the LED?

mindblown.gif

HaHa! I don't understand it either, I just accept it.

I thought that blue LEDs had a higher forward voltage. Actually, I didn't have 4 red so I went with blue. Mine is not super gainy, maybe that's why, but I don't play high gain stuff anyway so it works great for me. Here's a chart I found, not sure if it applies to 5mm LEDs:

http://www.oksolar.com/led/led_color_chart.htm

[selfdestroyer]

Wait, the CLR doesn't have to go directly between power and the LED?

mindblown.gif

HaHa! I don't understand it either, I just accept it.

I thought that blue LEDs had a higher forward voltage. Actually, I didn't have 4 red so I went with blue. Mine is not super gainy, maybe that's why, but I don't play high gain stuff anyway so it works great for me. Here's a chart I found, not sure if it applies to 5mm LEDs:

http://www.oksolar.com/led/led_color_chart.htm

Thanks for the link. Very interesting.

[m-Kresol]

Nice build!

Wait, the CLR doesn't have to go directly between power and the LED?

mindblown.gif

Haha, first I thought the same: this way the current will drop AFTER the led?!... man, we should both go back to the start for this rookie mistake. Obviously, it's Kirchhoff's first law. It basically states that the current going into a part, also goes out of it. Since the CLR sets a certain current limit, it also has to limit the current through the LED (if we assume that more current can pass through the LED than through the resistor - otherwise the CLR would be nonsense). caution: it makes a difference in voltage, but that doesn't matter at this point

[lincolnic]

Nice build!

Wait, the CLR doesn't have to go directly between power and the LED?

mindblown.gif

Haha, first I thought the same: this way the current will drop AFTER the led?!... man, we should both go back to the start for this rookie mistake. Obviously, it's Kirchhoff's first law. It basically states that the current going into a part, also goes out of it. Since the CLR sets a certain current limit, it also has to limit the current through the LED (if we assume that more current can pass through the LED than through the resistor - otherwise the CLR would be nonsense). caution: it makes a difference in voltage, but that doesn't matter at this point

I still don't quite understand it. If the purpose of the CLR is to keep the LED from burning out (and lowering the brightness in the process), then shouldn't it still be between power and the LED? I'm sure I'm missing something very simple and obvious, but if it's supposed to drop the current going to the LED, I still don't get how it does that if it's after the LED. Current is flowing from power through the LED to ground, no? How does the LED see a lowered voltage if it gets lowered after the LED?

Sorry to hijack your thread, G.G.!

[culturejam]

I still don't quite understand it. If the purpose of the CLR is to keep the LED from burning out (and lowering the brightness in the process), then shouldn't it still be between power and the LED?

Doesn't matter where the current gets limited, as long as it does. As long as the requisite resistance to limit the current happens between the positive and negative rails, the LED will work just fine. So you can put the CLR on the anode, or the cathode, or split the value into two resistors and have one on each side. Same thing.

m-keresol said it right in regard to Kirchoff's Current Law. "The Kirchhoff Current Law (KCL) states that the sum of all currents leaving a node in any electrical network is always equal to zero." http://www.resistorguide.com/kirchhoff-law/

[lincolnic]

Doesn't matter where the current gets limited, as long as it does. As long as the requisite resistance to limit the current happens between the positive and negative rails, the LED will work just fine. So you can put the CLR on the anode, or the cathode, or split the value into two resistors and have one on each side. Same thing.

m-keresol said it right in regard to Kirchoff's Current Law. "The Kirchhoff Current Law (KCL) states that the sum of all currents leaving a node in any electrical network is always equal to zero." http://www.resistorguide.com/kirchhoff-law/

Sorry, I'm really having trouble putting the pieces together. I'm not understanding how the LED can see a limited current when that limiting happens after the LED in the circuit. Electrons only flow in one direction, right? So if the resistor is post-LED, why isn't the LED blown up by the full 9V it receives first? How does the limited current go "backwards" to the LED? I think I need a more detailed explanation of how Kirchhoff's Current Law applies here - the math in your link is simple enough, but I'm having trouble understanding how that relates to this circumstance.

I'm really looking forward to the moment where this comes together and I slap myself on the head for not getting it sooner.