So that worked out great! Thank you very much.
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Show posts MenuQuote from: mjg on October 06, 2020, 05:49:20 AMOoh ok cool, thanks! I'll try it out in a day or two when I get some time again.
Try something like this:
One row of the switch connects the black and red of your jack. Much the same as what you have in the existing switch.
Another row of the switch has the middle lug going to battery -ve. The two outside lugs go to the cathode legs of the LED - one for blue, one for red (or whatever colour you've got).
The anode of the LED goes via a CLR, into the battery +ve.
Repeat for the 2nd switch.
(This is making some assumptions - that it's a common anode LED, and that the brightness will be OK with the same value CLR - you can put 2 CLRs in per LED instead, one for each colour, between the switch and cathode legs if you want to control the brightness differently for each colour)
Quote from: Matmosphere on October 05, 2020, 10:11:15 PMSo the amp has four channels. Bank 1 has 2 channels and bank 2 has two channels. Each throw of the switch changes them, they do not layer on top of one another. These switches have two colors. On the side you see three legs so one is ground and the other are + for each color. I just want the lights to illuminate depending on which channel, or at least bank I'm on.
I'm not really familiar with the amp. How many channels does it have, and can you describe how you want states LED's to show?
I'm generally against batteries, but if you rigged something up with two or three rechargeable double a's they would probably last forever in there.
Quote from: mjg on October 05, 2020, 08:54:27 PMIm going to use a 9v for the time being until I find a 9v barrel connector I like.
As a first step, you'll need to provide some power to the new housing, so that the LEDs have something to be powered by. Not sure if you've already done that and it's not in the picture.