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Of course you can't remove that IC. If I implied that, it was not of my intention. It's needed to supply the + and - 9 volts to the op amp. I used something similar using a 555 timer chip.

So the rest, other than, the 100uf cap is needed?

I know even with batteries we'd use diod protection in case the battery was installed improperly.

I wish I could get board results like this at home.

Anyone know what parts I wouldn't need using a 9v battery?
I am still going to buy the board, I'll just use jumpers to bypass what I don't need.

Any help would be appreciated.

So just revert back to the original design as far as the one chip goes?

20volt. 100uf on the tantalum. Using a 9v battery.

I was looking for a transparent boost for the internals of a guitar I'm making. I assume one could hook the out of the guitar before the jack, and put the boost circuit in between to knock it in and out of the circuit.

I won't be using an LED, so one of those and the resistor connected to it will not be needed. I was going to put a 500k multi-trim pot in place of an external pot. Going to set it once, and leave it. Same with the "warm" switch. Going to use a board mount single DIP switch. I want the most CLEAN boost I can get.

I was also wondering, since I am already in possession of one, would a 100uf tantalum cap work in place of a 100uf electrolytic? I'm sure it would be fine. Just asking.

Any advice offered will be welcome.